Php Update Database After Select Option Change Stack Overflow

Php Update Database After Select Option Change Stack Overflow Here's my question: how do i update my database from "pending" to "deliver" straight away after i change the select option from "pending" to "delivered"? reference no< td> status< td> $shopreference = $row['reference']; $status = $row['status']; if($status == 'pending') {$status = 'pending';} elseif($status == 'delivered'). Header("location:. update ?update=$lastenterid&parent id=$parent id"); then it will select the value by default that user have entered in index page form.

Php Update Database After Select Option Change Stack Overflow I would like to use ajax to the select option and save the data in the db, instead of using a select in a form with a button. this because i have one select for each row and every time i change the. When a selection is made in that drop down menu, a php mysql query is ran where the database will be updated with that value. i have all the pieces, all i need is the code that would be able to kick it all off. for instance when you hit submit on a form you would typically type out:. You wanted to know how to fix the update query, adding the where clause will do that. you need to wrap the entire thing in a

and use a hidden field for the id or use a and bind the id to the buttons value. The problem is when i tried to update my data like choose another option and saved it, nothing change. below are my codes. this is how i call my data from the database. twos< option> 2< option>.

Update Post Using Php Mysql Stack Overflow You wanted to know how to fix the update query, adding the where clause will do that. you need to wrap the entire thing in a and use a hidden field for the id or use a and bind the id to the buttons value. The problem is when i tried to update my data like choose another option and saved it, nothing change. below are my codes. this is how i call my data from the database.

twos< option> 2< option>. If ("$newprio" != "") { mysqli query ($con, "update table set prio='$newprio' where location='$loc' and alt code='$alt code';"); } again, when i click on the dropdown box and change the value, it changes on the webpage, but not inside of the database. is the onchange function in the right location? is the onchange function correct in this. What you should be doing in this case is letting the database update the values in place: set product current quantity = product current quantity $product quantity. where # ^^^^^ use the column, not a variable. the big problem here is one of improper handling of concurrency. If (isset ($ post ['add'])) { $addquery = "insert into producten (product, item, description, extra, valuta, price, nummer) values ('$ post [uproduct]','$ post [uitem]','$ post [udescription]','$ post [uextra]','$ post [uvaluta]','$ post [uprice]','$ post [unummer]')"; mysql query ($addquery, $con); }; $sql = "select * from producten"; $mydata. Learn on how to create a live update on select using php. an advance php code that can update a html select tag options. this code is very useful when you want to add some data in the select option tag.