Midterm Problem Set 3 Pdf The goal of this assignment is to give you a few more miscellaneous practice problems for the rst midterm. these will be harder than the problems on the midterm; the problems on the midterm will be of a similar avor. Problem 4: a cylindrical tank, 8 m tall and with diameter 2 m, how 5 much work is required to pump out half of the oil through a hole your answer in terms of and g (the acceleration of gravity). to raise the thin circle (thickness dy) shown to the top of the tank requires work dw = mgh.
Midterm Problem Set Pdf To help you with that, there is a version of each quiz posted on our course website without solutions (of course, there are solutions, too). problem 2. evaluate the integral z1 x3 ln(x) dx. problem 3. determine the shape (but not the exact numbers involved) of the partial fraction decompositions of: problem 4. evaluate dx. problem 5. Prepare for your calculus midterm part 2 of 2 with targeted practice questions and step by step video solutions. strengthen your understanding and boost your exam performance!. Practice problems for midterm 2 covering optimization, directional derivatives, probability, and multivariable integration. college level. These are a collection of practice problems for the second midterm exam. if you can do these problems (without looking at solutions), there is a high probability that you will do well on the exam.
Midterm 2 Pdf Midterm 2 Due Jul 22 At 11 59pm Points 30 Questions 30 Practice problems for midterm 2 covering optimization, directional derivatives, probability, and multivariable integration. college level. These are a collection of practice problems for the second midterm exam. if you can do these problems (without looking at solutions), there is a high probability that you will do well on the exam. Determine if each of the following series converges conditionally, converges abso lutely, or diverges. recall that a series is conditionally convergent if it converges but does not converge absolutely. show all your work and carefully and fully justify your reasoning, including naming the convergence test. n=1 ån!. There are 6 problems on this exam; problems 3 and 6 have multiple parts. there are 7 pages to the exam, including this page; all are single sided. check to see if any are missing. do your work in the space provided in this booklet. use the back of pages if you need more room. scientific calculators are allowed. no books or notes are allowed. We apply the integral test to f(x) = 1 x(ln(x))2 . observe that when x 3, f is non negative, decreasing and continuous. moreover, we have: therefore, by the integral test, the series x 1 is also convergent. x 3. Since the hypotenuse has length 3 = 12 ( 2)2, cos = 1= 3. 3=x4 3 < 0, so by the mean value theorem f must be one to one. (c) notice that f 1( 2) = 1. hence, (a) d(3x2)=dx = 3x2(d=dx) ln 3x2 = 3x2(d=dx)(x2 ln 3) = 3x2(2x ln 3). so the limit in the problem is e2=3. date: march 4, 2011. nd c = 3=2.
Electronic 2 Midterm 2 Solution Pdf Determine if each of the following series converges conditionally, converges abso lutely, or diverges. recall that a series is conditionally convergent if it converges but does not converge absolutely. show all your work and carefully and fully justify your reasoning, including naming the convergence test. n=1 ån!. There are 6 problems on this exam; problems 3 and 6 have multiple parts. there are 7 pages to the exam, including this page; all are single sided. check to see if any are missing. do your work in the space provided in this booklet. use the back of pages if you need more room. scientific calculators are allowed. no books or notes are allowed. We apply the integral test to f(x) = 1 x(ln(x))2 . observe that when x 3, f is non negative, decreasing and continuous. moreover, we have: therefore, by the integral test, the series x 1 is also convergent. x 3. Since the hypotenuse has length 3 = 12 ( 2)2, cos = 1= 3. 3=x4 3 < 0, so by the mean value theorem f must be one to one. (c) notice that f 1( 2) = 1. hence, (a) d(3x2)=dx = 3x2(d=dx) ln 3x2 = 3x2(d=dx)(x2 ln 3) = 3x2(2x ln 3). so the limit in the problem is e2=3. date: march 4, 2011. nd c = 3=2.
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