Solved Find The Value Of B If 1 E E2b E3b 9 Chegg Math advanced math advanced math questions and answers find the value of b for which 1 eb e2b e3b dots=9. We wish to find the number b b b for which 1 e b e e 9. 1\cdot e^ {b}\cdot e^ {2b}\cdot e^ {3b}\cdots = 9. 1⋅eb⋅e2b⋅e3b⋯9. a view the full answer previous questionnext question.
Solved 3 Find The Value Of B For Which 1 Eb E2b E3b 12 Chegg The formula for the sum of an infinite geometric series verifies the convergence criteria, as does the computed value of b, ensuring all arithmetic steps are consistent with mathematical principles. Step by step solution: step 1. we know that the sum of an infinite geometric series a ar ar2 is 1−ra, provided ∣r∣ <1. step 2. let a = 1 and r =eb, we have 1 eb e2b e3b = 1−eb1. step 3. substituting the values in the given equation, we have 1−eb1 = 9. step 4. solving the equation for b, we get, b= −ln(8). Explanation: analysis: = 1 e^ {b} e^ {2b} e^ {3b} e^ {4b} e^ {5b}=5 1 eb e2b e3b e4b e5b=5 whem b=0. ⋅ 1 e^ {0} e^ {0} e^ {0} e^ {0}\cdot 1 e0 e0 e0 e0⋅ =1 1 1 1 1 =5 b = 50.b=0 50.b=0. Our expert help has broken down your problem into an easy to learn solution you can count on. here’s the best way to solve it. 1 eb e2b e3b = 1 5 ==> 1 eb (eb)2 (eb)3 = 1 5 it is a geometric series with a common ratio of r … not the question you’re looking for? post any question and get expert help quickly.
Solved 3 Find The Value Of B For Which 1 Eb E2b E3b 12 Chegg Explanation: analysis: = 1 e^ {b} e^ {2b} e^ {3b} e^ {4b} e^ {5b}=5 1 eb e2b e3b e4b e5b=5 whem b=0. ⋅ 1 e^ {0} e^ {0} e^ {0} e^ {0}\cdot 1 e0 e0 e0 e0⋅ =1 1 1 1 1 =5 b = 50.b=0 50.b=0. Our expert help has broken down your problem into an easy to learn solution you can count on. here’s the best way to solve it. 1 eb e2b e3b = 1 5 ==> 1 eb (eb)2 (eb)3 = 1 5 it is a geometric series with a common ratio of r … not the question you’re looking for? post any question and get expert help quickly. Find the value of b for which 1 eb e2b e3b = 9. to solve this, notice that the expression is a geometric series with a first term of 1 and a common ratio of eb. we can use the formula for the sum of an infinite geometric series to find b. the value of b that satisfies the equation is b = ln (8) ln (e), which simplifies to b = 2. Find (a) a, (b) a b, (c) a − b, (d) ‖ a b ‖, and $ (e)\|\mathbf {a} \… video answer: all right, everybody. and welcome back to new murad. this is kevin chirac. let's consider this expression. and we're curious about what letter b is going to make all of this be true. so let's take a m. Divide both sides by $$e^b$$eb to solve for $$e^b$$eb: $$e^ {b} = \frac {9} {10}$$eb = 109 take the natural logarithm of both sides to solve for $$b$$b: $$b = \ln \frac {9} {10}$$b= ln 109 therefore, the correct answer is $$b = \ln \frac {9} {10}$$b = ln 109 , which corresponds to option b. The value of b for which the sum of the infinite geometric series 1 eb e2b e3b equals 9 is found by using the formula for an infinite geometric series and solving for b, which results in b = ln (8 9).
Solved Find The Value Of B For Which 1 Eb E2b E3b Chegg Find the value of b for which 1 eb e2b e3b = 9. to solve this, notice that the expression is a geometric series with a first term of 1 and a common ratio of eb. we can use the formula for the sum of an infinite geometric series to find b. the value of b that satisfies the equation is b = ln (8) ln (e), which simplifies to b = 2. Find (a) a, (b) a b, (c) a − b, (d) ‖ a b ‖, and $ (e)\|\mathbf {a} \… video answer: all right, everybody. and welcome back to new murad. this is kevin chirac. let's consider this expression. and we're curious about what letter b is going to make all of this be true. so let's take a m. Divide both sides by $$e^b$$eb to solve for $$e^b$$eb: $$e^ {b} = \frac {9} {10}$$eb = 109 take the natural logarithm of both sides to solve for $$b$$b: $$b = \ln \frac {9} {10}$$b= ln 109 therefore, the correct answer is $$b = \ln \frac {9} {10}$$b = ln 109 , which corresponds to option b. The value of b for which the sum of the infinite geometric series 1 eb e2b e3b equals 9 is found by using the formula for an infinite geometric series and solving for b, which results in b = ln (8 9).
Comments are closed.