Search In A Rotated Sorted Array Leetcode 33 Full Solution With Examples Study Algorithms

By themelower On Jul 19, 2025

Search In Rotated Sorted Array Ii Leetcode Given the array nums after the possible rotation and an integer target, return the index of target if it is in nums, or 1 if it is not in nums. you must write an algorithm with o (log n) runtime complexity. Class solution { public: int search(vector& nums, int target) { int l = 0; int r = nums.size() 1; while (l <= r) { const int m = (l r) 2; if (nums[m] == target) return m; if (nums[l] <= nums[m]) { nums[l m] are sorted. if (nums[l] <= target && target < nums[m]) r = m 1; else l = m 1; } else { nums[m n 1] are sorted. if.

Leetcode Search In Rotated Sorted Array Ii Problem Solution In depth solution and explanation for leetcode 33. search in rotated sorted array in python, java, c and more. intuitions, example walk through, and complexity analysis. better than official and forum solutions.

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Search in a Rotated Sorted Array (LeetCode 33) | Full solution with examples | Study Algorithms

Search in a Rotated Sorted Array (LeetCode 33) | Full solution with examples | Study Algorithms

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