How To Secure File Upload With Flask Python The docs say you should use enctype="multipart form data". also, i might try method="post" (uppercase), if only because defensive coding is a good habit, the defensive maneuver here being not assuming that flask is bug free. Flask needs you to use square brackets [] when handling requests. in main.py replace that route with: if request.method == "post": userfile = request.files['ufile'] filename = secure filename(userfile.filename) userfile.save(path.join(app.config['upload folder'], filename)) return "uploaded" that's all, and your issues should be solved.
How To Secure File Upload With Flask Python Try using flask's recommended format for file uploads for better error checking. i'm guessing that 'file' doesn't exist in the dictionary, so it faults when checking for value. 'file' should be replaced with the name of the file input element, thus if you have , then then it should be request.files ['file2']. Also, i might try method="post" (uppercase), if only because defensive coding is a good h more. the docs say you should use enctype="multipart form data".
How To Secure File Upload With Flask Python
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