Php Fatal Error Uncaught Mysqli Sql Exception Column Topic Cannot Be

Fatal Error Uncaught Mysqli Sql Exception Access Denied For User Root I am trying to upload to my database a user entry under a subtopic. when i enter something into the textarea and click the add comment button, i get these two errors: fatal error: uncaught. There's most likely an sql special character in one of the values that is breaking the sql query syntax. you should build the sql query statement in a php variable, as this allows you to echo it to see what it actually is.

Php Fatal Error Uncaught Mysqli Sql Exception Column Topic Cannot Be Fatal error: uncaught mysqli sql exception: you have an error in your sql syntax; check the manual that corresponds to your mariadb server version for the right syntax to use near '?' at line 1 in c:\xampp\htdocs\test\following histories v1 :418 stack trace: #0 c:\xampp\htdocs\test\following histories v1 (418): mysqli query (object. One of the most common causes of the mysqli sql exception is incorrect database credentials. ensure that the hostname, username, password, and database name are correctly specified in your php code or configuration file. Are you calling anything else that uses a prepared query between the calls to this method? the most likely cause is because $iitemid and $itermid are not static, and the instances of them. You're throwing mysqli sql exception for all errors and warnings due to your mysqli report(mysqli report all); line. your php code is not catching that exception (i.e. it's not in a try{} block with an appropriate catch(){} block), and uncaught exceptions are fatal.

Php Fatal Error Uncaught Mysqli Sql Exception Column Topic Cannot Are you calling anything else that uses a prepared query between the calls to this method? the most likely cause is because $iitemid and $itermid are not static, and the instances of them. You're throwing mysqli sql exception for all errors and warnings due to your mysqli report(mysqli report all); line. your php code is not catching that exception (i.e. it's not in a try{} block with an appropriate catch(){} block), and uncaught exceptions are fatal. You can disable mysqli error reporting if you really wish so, or you can just catch the exception and handle it however you want. it's a standard php behaviour. You have configured mysqli report (mysqli report all), causing your program to treat both errors and warnings as mysqli sql exception exceptions. your php code is not catching this exception, meaning it is not encapsulated in a try {} block with a corresponding catch () {} block. "fatal error: uncaught mysqli sql exception" is just part of the error message. what else it tells? a little tip: your mysqli extension is configured to throw exceptions on error (which is a great thing!), so you don't need all the error handling code. just remove all the if that check an error condition and your code will be greatly simplified. Please try it with \mysqli sql exception and verify that the line where the exception occurs is actually in your try block. it sounds very much like a namespace problem and or you're simply not including all relevant code in the try catch block.