145 fun factsabout the digestive system represents a topic that has garnered significant attention and interest. The sum of the first nth term of a geometric series is 145 ... What is n and the common ratio? Question #33eb8 - Socratic. First, subtract #color (red) ($145)# from each side of the equation to isolate the #w# term while keeping the equation balanced:
From another angle, 196 ft.^2 Refer to figures below From the given data we have D_1=6 ft. Equally important, as we can see in Fig. In this context, (a) r_2/(H-h)=r_1/H 2/(H-12)=3/H => 2H=3H-36 => H=36 Since s=sqrt(2)*r (see Fig.(b)) s_1=3sqrt(2) s_2=2sqrt(2 Area of bases S_(b1)=s_1^2=(3sqrt(2))^2=18 S_(b2)=s_2^2=(2sqrt(2))^2=8 Side of the slanted trapezoid (see Fig.(c)) x^2=h^2+(r_1-r_2)^2 x=sqrt(12^2+1^2 ... Maria had 105 beads to start with.
First define the number of beads each girl had using variables. Let the number of beads that Maria had be x Together they had 250, so the number of beads that Farida had is 250-x Maria uses 18 beads, so she has (x-18) left Farida gives 2/5 of her beads away, so she has 3/5(250-x) left Now they have the same number of beads: x-18 = 3/5(250-x)" "larr multiply ... An isosceles triangle has sides A, B, and C, such that sides ... 12.04 (approx) Let the length of side A or B = x and base is 16. It's important to note that, so the height is sqrt [x^2 - (16/2)^2] Now the area of triangle = 1/2 * base * height = 1/2 * 16 * sqrt [x^2 - (16/2)^2].
Therefore, 1/2 * 16 * sqrt [x^2 - (16/2)^2] = 72 or, sqrt [x^2 - 8^2]=72/8 or, x^2 - 64 = 81 or, x^2 = 145 or, x = sqrt 145 = 12.04 (approx) Calculator gives --> sin x = 0.5623 --> x = 34.22 and x = 180 - 34.22 = 145.78 deg. Equally important, extended answers: x = 34.22 + k360 deg x = 145.78 + k360 deg 2. cos x = 0.8963 --> x = +- 26.32 deg Extended answers: x = +- 26.32 + k360 deg. tan x = -2.89 --> x = -70.93 and x = -70.93 + 180 = 109.09 deg Extended answers: x = 109.09 + k180 deg
If the measures of a triangle are 90°, 55°, and 3x - Socratic. => x = 10 The measures (angles) of a triangle sum to 180^o. =>90 + 55 + (3x+5) = 180 =>145 + (3x+5)=180 =>3x + 5 = 35 =>3x = 30 => x = 10 Point A is at # (-7 ,3 )# and point B is at # (5 ,4 )#. A' = (7, -3) The distance has decreased by sqrt(145) - sqrt(53) ~~ 4.76 Given: A(-7, 3), B(5, 4) Point A is rotated pi clockwise about the origin.
Can you help me with finding perimeter of this sector fragment?. This perspective suggests that, i'll ask more questions if I need more help. A triangle has sides A, B, and C. The angle between sides A ...
The length of side A is 10.145 (3dp) The angle between sides A and B is /_c= pi/8=180/8=22.5^0 The angle between sides B and C is /_a= pi/12=180/12=15^0 Given C=15; A=?.
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